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Ответ:

1)

[tex]6 - (3 \sqrt{ \frac{4}{9} } + \sqrt{0.25} ) = 6 - (3 \times \frac{2}{3} + 0.5) = 6 - 2.5 = 3.5[/tex]

3)

[tex] \frac{ \sqrt{225} + 3 \sqrt{121} }{ \frac{2}{3} \sqrt{0.09} + 0.78 \sqrt{100} } = \frac{15 + 3 \times 11}{ \frac{2}{3} \times 0.3 + 0.78 \times 10} = \frac{48}{ \frac{2}{3} \times \frac{3}{10} + \frac{78}{100} \times 10} = \frac{48}{ \frac{1}{5} + \frac{78}{10} } = \frac{48}{ \frac{1}{5} + \frac{39}{5} } = \frac{48}{ \frac{40}{5} } = \frac{48}{8} =6[/tex]