помогите решить ПРИМЕР!!!! (16 22/45*0,5-1 61/72:0,5)*5/7+198,9:(9 1/2+23/40:2 3/10)+13 1/2*0,1. Created by Эля5. algebra-ru

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Эля5 @Эля5

October 2021 1 18 Report

помогите решить ПРИМЕР!!!!

(16 22/45*0,5-1 61/72:0,5)*5/7+198,9:(9 1/2+23/40:2 3/10)+13 1/2*0,1

Answers & Comments

fou

$(16\frac{22}{45}\cdot 0,5-1\frac{61}{72}:0,5)\cdot \frac{5}{7}+198,9:(9\frac{1}{2}+\frac{23}{40}:2\frac{3}{10})+13\frac{1}{2}\cdot0,1=\\ \\=(\frac{742}{45}\cdot \frac{1}{2}-\frac{133}{72}\cdot 2)\cdot \frac{5}{7}+\frac{1989}{10}:(\frac{19}{2}+\frac{23}{40}:\frac{23}{10})+\frac{27}{2}\cdot \frac{1}{10}=\\ \\ =\frac{371}{45}\cdot \frac{5}{7}-\frac{266}{72}\cdot \frac{5}{7}+\frac{1989}{10}:(\frac{19}{2}+\frac{1}{4})+\frac{27}{20}=\\ \\=$

$=\frac{371}{9\cdot 7}-\frac{1330}{8\cdot9\cdot7}+\frac{1989}{10}:\frac{39}{4}+\frac{27}{20}=\frac{371}{9\cdot 7}-\frac{1330}{8\cdot9\cdot7}+\frac{102}{5}+\frac{27}{20}=\\ \\ =\frac{2968-1330}{8\cdot9\cdot 7}+\frac{408+27}{20}=\frac{26}{8}+\frac{87}{4}=\frac{13}{4}+\frac{87}{4}=\frac{100}{4}=25$