Ответ:

[tex]f(x)=6x^{0,5}+x^{-2}\ \ ,\qquad formyla:\ \ (x^{n})'=nx^{n-1}\\\\\\f'(x)=6\cdot 0,5x^{-0,5}-2x^{-3}=\dfrac{3}{\sqrt{x}}-\dfrac{2}{x^3}[/tex]