Решите уравнение 5^-1/2*(0,2)^x+0,5=5^-2*(0,04)^x. Created by n0a0s0t0y0a. matematika-ru

2*(0,2)^x+0,5=5^-2*(0,04)^x...

n0a0s0t0y0a @n0a0s0t0y0a

July 2022 1 7 Report

Решите уравнение
5^-1/2*(0,2)^x+0,5=5^-2*(0,04)^x

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NNNLLL54

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$5^{-1/2}\cdot (0,2)^{x+0,5}=5^{-2}\cdot (0,04)^{x}\\\\\\0,2=\frac{2}{10}=\frac{1}{5}=5^{-1}\; ,\; \; 0,04=\frac{4}{100}=\frac{1}{25}=5^{-2}\\\\\\5^{-1/2}\cdot 5^{-x-0,5}=5^{-2}\cdot 5^{-2x}\\\\5^{-x-1}=5^{-2x-2}\; \; \Rightarrow \; \; -x-1=-2x-2\; \; ,\; \; x=-1\\\\Otvet:\; \; x=-1\; .$

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chast dohoda kotoraya otkladyvaetsya dlya udovletvoreniya budushih potrebnostej eto

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chast dohoda kotoraya otkladyvaetsya dlya udovletvoreniya budushih potrebnostej eto

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chast dohoda kotoraya otkladyvaetsya dlya udovletvoreniya budushih potrebnostej eto

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77^x+1-147^x-1+2*7^x=48...