2,0,5,1,3...

ChBomshel @ChBomshel

July 2022 1 3 Report

найдите выражение: 4)2х+8/х+1 при х=1/2,0,5,1,3

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Universalka

Verified answer

$2x+\frac{8}{x+1} \\\\1)x=\frac{1}{2}\\\\2*\frac{1}{2}+\frac{8}{\frac{1}{2} +1}=1+\frac{8}{\frac{3}{2}} =1+\frac{8*2}{3}=1+5\frac{1}{3} =\boxed{6\frac{1}{3}}\\\\\\2)x=0,5\\\\2*0,5+\frac{8}{0,5+1}=1+\frac{8}{1,5}=1+5\frac{1}{3}=\boxed{6\frac{1}{3}} \\\\\\3)x=1\\\\2*1+\frac{8}{1+1}=2+\frac{8}{2}=\boxed6\\\\\\4)x=3\\\\2*3+\frac{8}{3+1}=6+\frac{8}{4}=\boxed8$

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