решите уравнения через Дискриминант 1)Х2+2x - 7 =0 2)X2+3x-1 1/2=0. Created by cosmos33791. algebra-ru

2=0...

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решите уравнения через Дискриминант

1)Х2+2x - 7 =0

2)X2+3x-1 1/2=0

nKrynka 1) Х² + 2x - 7 = 0
D = 4 + 4*1*7 = 32
x₁ = (- 2 - 4√2)/2
x₁ = - 1 - 2√2
x₂ = (- 2 + 4√2)/2
x₂ = - 1 + 2√2

2) X² + 3x - 1(1/2) = 0
D = 9 + 4*1*(3/2) = 15
x₁ = (- 3 - √15)/2
x₂ = (- 3 + √15)/2

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Apofeoz $1)\ x^2+2x-7=0,\\D=2^2-4\bullet1\bullet(-7)=4+28=32,\\\\x_1=\frac{-2+\sqrt{32}}{2}=\frac{-2+4\sqrt2}{2}=-1+2\sqrt2,\\\\x_2=-1-2\sqrt2.

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$2)\ x^2+3x-1\frac{1}{2}=0\ 
|\bullet2,\\2x^2+6x-3=0,\\D=6^2-4\bullet2\bullet(-3)=36+24=60,\\\\x_1=\frac{-6+\sqrt{60}}{2\bullet2}=\frac{-6+2\sqrt{15}}{4}=\frac{-3+\sqrt{15}}{2},\\\\x_2=\frac{-3-\sqrt{15}}{2}.$

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