помогите плз на паре сижу
lim x->9 (x-9)/(√x-3)
lim x->3 (4x² -11x-3)/(5x² -16x+3)
lim x->бесконечности
(20 x² -5x+4)/(20x-5)
lim x->9 (x-9)/(√x-3)
lim x->3 (4x² -11x-3)/(5x² -16x+3)
lim x->бесконечности
(20 x² -5x+4)/(20x-5)
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