Ответ:
y=cos(2x)cos(pi/2)-sin(2x)sin(pi/2)
y=cos(2x)×0-sin(2x)×1
y=0-sin(2x)
y=-sin(2x)
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Ответ:
y=cos(2x)cos(pi/2)-sin(2x)sin(pi/2)
y=cos(2x)×0-sin(2x)×1
y=0-sin(2x)
y=-sin(2x)
y=-sin(2x)