[tex]\displaystyle3x^2+12=30x \quad:3\\x^2+4=10x\\x^2-10x+4=0\\\\D=100-16=84\\x = \frac{10\pm\sqrt{84}}{2} = 5\pm\sqrt{21}[/tex]
Ответ:
5+√21; 5-√21
Объяснение:
3х² + 12 = 30x;
3х²-30х+12=0 сократим на 3
х²-10х+4=0
х=(10±√(100-16))/2=(10±√84)/2=(10±2√21)/2=2(5±√21)/2=5±√21
х1=5+√21; х2=5-√21
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[tex]\displaystyle3x^2+12=30x \quad:3\\x^2+4=10x\\x^2-10x+4=0\\\\D=100-16=84\\x = \frac{10\pm\sqrt{84}}{2} = 5\pm\sqrt{21}[/tex]
Verified answer
Ответ:
5+√21; 5-√21
Объяснение:
3х² + 12 = 30x;
3х²-30х+12=0 сократим на 3
х²-10х+4=0
х=(10±√(100-16))/2=(10±√84)/2=(10±2√21)/2=2(5±√21)/2=5±√21
х1=5+√21; х2=5-√21