Ответ:
1. [tex](3a-2b)(3a^{3} +2b^{2} )=(3*\frac{1}{3} -2*\frac{1}{2} )(3(\frac{1}{3} )^{3} +2(\frac{1}{2} )^{2} )=(1-1)(3*\frac{1}{27} +2*\frac{1}{8} )=0*(\frac{1}{9} +\frac{1}{4} )=0[/tex]
2. [tex]3a^{2} +7ab+2b^{2} =3*2^{2} +7*2*(-1)+2*(-1)^{2} =3*4-14+2*1=12-14+2=14-14=0[/tex]
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Ответ:
1. [tex](3a-2b)(3a^{3} +2b^{2} )=(3*\frac{1}{3} -2*\frac{1}{2} )(3(\frac{1}{3} )^{3} +2(\frac{1}{2} )^{2} )=(1-1)(3*\frac{1}{27} +2*\frac{1}{8} )=0*(\frac{1}{9} +\frac{1}{4} )=0[/tex]
2. [tex]3a^{2} +7ab+2b^{2} =3*2^{2} +7*2*(-1)+2*(-1)^{2} =3*4-14+2*1=12-14+2=14-14=0[/tex]