Ответ:
Пошаговое объяснение:
sin2α=2sinαcosα=2cosα√(1-cos²α)=(2/3)√(1-(1/9))=(2/3)√(8/9)=(2/3)(2/3)√2=
(4√2)/9
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Ответ:
Пошаговое объяснение:
sin2α=2sinαcosα=2cosα√(1-cos²α)=(2/3)√(1-(1/9))=(2/3)√(8/9)=(2/3)(2/3)√2=
(4√2)/9