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mudblood8
@mudblood8
July 2022
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cos t > корень квадратный 2/2. t относится [-pi/2;pi/2]
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sedinalana
Cost>√2/2
t∈(-π/4+2πk;π/4+2πk,k∈z)
t∈(-π/4;π/4)
2 votes
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Answers & Comments
t∈(-π/4+2πk;π/4+2πk,k∈z)
t∈(-π/4;π/4)