9ab/35m^7 : 45a^2b^6/21m^8. Created by lizalizamuntianmama. algebra-ru

21m^8...

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$\displaystyle\bf\\\dfrac{9ab}{35m^{7} }:\dfrac{45a^{2} b^{6} }{21m^{8} } = \dfrac{9ab}{35m^{7} }\cdot\dfrac{ 21m^{8} }{45a^{2} b^{6} } =\dfrac{9\cdot ab\cdot7\cdot3\cdot m^{7} \cdot m}{7\cdot 5\cdot m^{7} \cdot 9\cdot 5\cdot ab\cdot a\cdot b^{5} } =\\\\\\=\dfrac{3m}{25ab^{5} }$

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$\dfrac{9ab}{35m^7}:\dfrac{45a^2b^6}{21m^8}=\dfrac{9ab}{35m^7}\cdot\dfrac{21m^8}{45a^2b^6}=\dfrac{1\cdot3m}{5\cdot5ab^5}=\dfrac{3m}{25ab^5}$

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15 652dd6a45ca66

20 1 2 649deef60cf0e

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