5^log25_(2^1/2-2)^2 + 3^log9_(2^1/2+2)^2 ПОМОГИТЕ. Created by Denfai. matematika-ru

Ответ:4Пошаговое объяснение:

2+2)^2 ПОМОГИТЕ...

Denfai @Denfai

June 2022 1 11 Report

5^log25_(2^1/2-2)^2 + 3^log9_(2^1/2+2)^2 ПОМОГИТЕ

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IrkaShevko

Verified answer

Ответ:

Пошаговое объяснение:

$5^{log_{25}(2^{0,5}-2)^2}+3^{log_{9}(2^{0,5}+2)^2} = 5^{log_{5^2}(2^{0,5}-2)^2}+3^{log_{3^2}(2^{0,5}+2)^2}=\\\\5^{log_{5}(|2^{0,5}-2|)}+3^{log_{3}(|2^{0,5}+2|)}=|2^{0,5}-2| + |2^{0,5}+2|=2-2^{0,5}+2+2^{0,5}=4$

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IrkaShevko да, точно про модуль забыла

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