V(C2H2) = 2.24 l

η(C6H6) = 65%

m(C6H6) - ?
n(C2H2) = 2.24 l / 22.4 l / mol = 0.1 mol

3C2H2(акт. C , t*C) = C6H6

3n(C2H2) = n(C6H6); n(C6H6) = 0.1 mol / 3 = 0.033 mol ;

m(C6H6 теоретического) = 0.033 mol * 78 g / mol = 2.574 g ;

m(C6H6 практического) = 2.574 g * 0.65 = 1.6731 g = 1.673 g ;

Ответ: 1.673 g .