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olyaolya1207
@olyaolya1207
July 2022
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sin(п/10-x/2)=корень из 2/2
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nKrynka
sin(π/10 - x/2) = √2/2
π/10 - x/2 = (-1)^narcsin(√2/2) + πn, n∈Z
π/10 - x/2 = (-1)^n(π/4) + πn, n∈Z
x/2 = π/10 - (-1)^n(π/4) + πn, n∈Z
x = π/5 - (-1)^n(π/2) + 2πn, n∈Z
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Answers & Comments
π/10 - x/2 = (-1)^narcsin(√2/2) + πn, n∈Z
π/10 - x/2 = (-1)^n(π/4) + πn, n∈Z
x/2 = π/10 - (-1)^n(π/4) + πn, n∈Z
x = π/5 - (-1)^n(π/2) + 2πn, n∈Z