Ответ:
b=0
Объяснение:
(b+2)(x–1)=2(x+b–1)
bx–b+2x–2=2x+2b–2
bx–b+2x–2x–2b= –2+2
bx–3b=0
b(x–3)=0
x–3=0
x=3
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Ответ:
b=0
Объяснение:
(b+2)(x–1)=2(x+b–1)
bx–b+2x–2=2x+2b–2
bx–b+2x–2x–2b= –2+2
bx–3b=0
b(x–3)=0
b=0
x–3=0
x=3