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zhambulat
@zhambulat
September 2021
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помогите 3 вариант 1 задание 3 и 4 пожалуйста
упростите ctg^2(п-а)-1/2tg(3п/2-a)
упростите cos(2п-2а)+sin^2a/cos п/2+2a
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sedinalana
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(сtg²a-1)/2ctga=(cos²a/sin²a -1):2cosa/sina=(cos²a-sin²a)/sin²a*2sina/cosa=
=cos2a*2sina/[sin²a*cosa]=4cos2a/sin2a=4ctg2a
(cos2a+sin²a/(-sin2a)=-cos²a/2sinacosa=-1/2*ctga
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Answers & Comments
Verified answer
(сtg²a-1)/2ctga=(cos²a/sin²a -1):2cosa/sina=(cos²a-sin²a)/sin²a*2sina/cosa==cos2a*2sina/[sin²a*cosa]=4cos2a/sin2a=4ctg2a
(cos2a+sin²a/(-sin2a)=-cos²a/2sinacosa=-1/2*ctga