Ответ:
а) (2-n)(1+2n)-(1+n)(3n-n³) =2+4n-n+2n²-(3n-n³+3n²-n²) =2+4n-n+2n²-3n+n-3n²+n²= n+2
б) (3x+5) (9x²+15x+25) =27x³+45x²+75x+45x²+75x+125=27x³+90x²+150x+125
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Ответ:
а) (2-n)(1+2n)-(1+n)(3n-n³) =2+4n-n+2n²-(3n-n³+3n²-n²) =2+4n-n+2n²-3n+n-3n²+n²= n+2
б) (3x+5) (9x²+15x+25) =27x³+45x²+75x+45x²+75x+125=27x³+90x²+150x+125