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bornica78
@bornica78
August 2021
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упростите выражение:
1.2cos²(α/2)-cos α
2.4sin²(α/2)+2cos α+3
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kirichekov
Verified answer
1. cosα=cos(2*α/2)=cos²(α/2)-sin²(α/2)
2coos²(α/2)-(cos²(α/2)-sin²(α/2))=2cos²(α/2)-cos²(α/x)+sin²(α/2)=cos²(α/2)+sin²(α/2)=1
2. 4sin²(α/2)+2cosα+3=4sin²(α/2)+2(cos²(α/2)-sin²(α/2))+3=4sin²(α/2)+2cos²(α/2)-2sin²(α/2)+3=2sin²(α/2)+2cos²(α/2)+3=2(sin²(α/2)+cos²(α/2))+3=2+3=5
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Answers & Comments
Verified answer
1. cosα=cos(2*α/2)=cos²(α/2)-sin²(α/2)2coos²(α/2)-(cos²(α/2)-sin²(α/2))=2cos²(α/2)-cos²(α/x)+sin²(α/2)=cos²(α/2)+sin²(α/2)=1
2. 4sin²(α/2)+2cosα+3=4sin²(α/2)+2(cos²(α/2)-sin²(α/2))+3=4sin²(α/2)+2cos²(α/2)-2sin²(α/2)+3=2sin²(α/2)+2cos²(α/2)+3=2(sin²(α/2)+cos²(α/2))+3=2+3=5