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rodgerman
@rodgerman
July 2022
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Решите тригонометрическое уравнение:
sin^2*x/2=3cos^2*x/2.
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avilov41
sin^2x/2=3cos^2x/2.
Решение.
tg^2x/2=3,
x/2=(+)(-)argtg√3+πn,n∈z;
x=(+(-) 2π/3+2πn,n∈z.
Ответ. x=(+)(-)2π/3+2πn,n∈z.
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Answers & Comments
Решение.
tg^2x/2=3,
x/2=(+)(-)argtg√3+πn,n∈z;
x=(+(-) 2π/3+2πn,n∈z.
Ответ. x=(+)(-)2π/3+2πn,n∈z.