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mrlukecage
@mrlukecage
July 2022
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lim (2^(2n-1)+3*5^n)/(2^(2n+1)+4*5^(n-1)) n->бесконеч.
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yugolovin
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yugolovin
Это все чудеса TEXа - как получилось, причем дважды, <br/> - выше моего разумения. Скажу спасибо любому, кто подскажет, откуда такой странный результат и как с ним бороться
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