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Кошечка01
@Кошечка01
August 2022
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Зная, что cosx=3/13 и x∈(3π/2;2π), вычисли: cos2x−3,1
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sedinalana
Verified answer
Cos2x=2cos²x-1
cos2x=2*9/169-1=18/169-1=-151/169
cos2x-3,1=-151/169-3 1/10=-1510/1690-3 169/1690=-3 1679/1690
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Verified answer
Cos2x=2cos²x-1cos2x=2*9/169-1=18/169-1=-151/169
cos2x-3,1=-151/169-3 1/10=-1510/1690-3 169/1690=-3 1679/1690