Найдите 3cosα,если sinα=-(2√2)/3 и α ϵ (3π/2;2π).. Created by lianadyusmetova. algebra-ru

2;2π)...

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July 2022 1 8 Report

Найдите 3cosα,если sinα=-(2√2)/3 и α ϵ (3π/2;2π).

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lara164

Verified answer

Sinα = -(2√2)/3 ⇒ sin²α = (-(2√2)/3)² = 8/9
sin²α + cos²α = 1 ⇒ cos² α = 1-sin²α ⇒cos²α = 1-8/9 = 1/9
cosα = √1/9 = 1/3 ( cosα = - 1/3 -не подходит для α ϵ (3π/2;2π))
3 cosα = 3*1/3 = 1
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