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@79854785416
July 2022
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Найдите tg a, если sin a = -2корня 2/3 и а принадлежит (3пи/2;2пи)
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rima134
Sina=-2v2/3 sin^2a=8/9 cos^2a=1-sin^2a=1-8/9=1/9 cosa=+-1/3 tg=sina/cosa=
(-2v2/3)/1/3=-2v2 tg2=2v2
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(-2v2/3)/1/3=-2v2 tg2=2v2