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Anny1117
@Anny1117
March 2022
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2,3,7 методом интервалов
СРОЧНО!!!!
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ItalicOpen
2. x1 = 3/2 x2 = -1/3
x ∈ (-∞; -1/3)∪(3/2;∞)
3. x1 = 4/5 x2= -5/2
x ∈ (-∞; -5/2)∪(4/5;∞)
7. x1 = 0 x2= 1 x3= 2 x4= 3
x ∈ (-∞; 0)∪(1;2)∪(3;∞)
1 votes
Thanks 2
300228229
7. x1 = 0 x2= 1 x3= 2 x4=
= 3 x ∈ (-∞; 0)∪(1;2)∪(3;∞)
2. x1 = 3/2 x2 = -1/3
x ∈ (-∞; -1/3)∪(3/2;∞)
3. x1 = 4/5 x2= -5/2
x ∈ (-∞; -5/2)∪(4/5;∞)
1 votes
Thanks 1
300228229
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Answers & Comments
x ∈ (-∞; -1/3)∪(3/2;∞)
3. x1 = 4/5 x2= -5/2
x ∈ (-∞; -5/2)∪(4/5;∞)
7. x1 = 0 x2= 1 x3= 2 x4= 3
x ∈ (-∞; 0)∪(1;2)∪(3;∞)
7. x1 = 0 x2= 1 x3= 2 x4=
= 3 x ∈ (-∞; 0)∪(1;2)∪(3;∞)
2. x1 = 3/2 x2 = -1/3
x ∈ (-∞; -1/3)∪(3/2;∞)
3. x1 = 4/5 x2= -5/2
x ∈ (-∞; -5/2)∪(4/5;∞)