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dasha3336
@dasha3336
July 2022
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cos (П/2+t)= - корень 3/2
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Amigo3
0,5*π+t1=5*π/6+2*π*n⇒t1=(5*π/6)+2*π*n-(3*π/6)=2*π*n+π/3.
0,5*π+t2=7*π/6+2*π*n⇒
(7*π/6)+2*π*n-(3*π/6)=2*π*n+(2*π/3).
То есть имеем 2 корня с периодическим повторением.
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Answers & Comments
0,5*π+t2=7*π/6+2*π*n⇒(7*π/6)+2*π*n-(3*π/6)=2*π*n+(2*π/3).
То есть имеем 2 корня с периодическим повторением.