sin П/3 + 2cos П/4 - ctg^2 3П/4 + tg П/6 + sin 3П/2. Created by shusam. algebra-ru

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August 2021 1 9 Report

sin П/3 + 2cos П/4 - ctg^2 3П/4 + tg П/6 + sin 3П/2

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BETTELGEUSE Sin(π/3)=sin(60°)=√3/2.
cos(π/4)=cos(45°)=√2/2.
ctg²(3π/4)=ctg²(135°)=ctg²(π/2+45°)=tg²(45°=1.
tg(π/6)=tg(30°)=√3/3.
sin(3π/2)=sin(270°)=sin(180°+90°)=-sin(90°)=1.
√3/2+√2-1+√3/3-1=5√3/6+√2-2.

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