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miss12345
@miss12345
August 2022
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помогите найти производную!пожалуйста
y=sin^2*2x*cosx/2
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sedinalana
Verified answer
Y`=(sin²2x)`*(sin2x)`*(2x)`*cosx/2+sin²x*(cosx/2)`*(x/2)`=
=2sin2x*cos2x*2*cosx/2+sin²2x*(-sinx/2)*1/2=
=2sin4x*cosx/2-1/2*sin²2x*sinx/2
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Answers & Comments
Verified answer
Y`=(sin²2x)`*(sin2x)`*(2x)`*cosx/2+sin²x*(cosx/2)`*(x/2)`==2sin2x*cos2x*2*cosx/2+sin²2x*(-sinx/2)*1/2=
=2sin4x*cosx/2-1/2*sin²2x*sinx/2