Home
О нас
Products
Services
Регистрация
Войти
Поиск
andromeda31
@andromeda31
August 2022
2
12
Report
a) Решите уравнение 3 cos^2x+cosx-4=0
б)Укажите корни, принадлежащие отрезку [п/2;3п]
Please enter comments
Please enter your name.
Please enter the correct email address.
Agree to
terms of service
You must agree before submitting.
Send
Answers & Comments
skyne8
Verified answer
=3(2(cosx)^2 -1)+cosx-4=0,
6cos^2(x)+cosx-7=0,
(cosx -1)(cosx -14/6)=0, cosx=1,
x=2п
3 votes
Thanks 2
jazka001
Отметим cosх-у и будем решить уравнения 3у^2+у-4=0 D=1+48=49 y1=1 y2=-4/3 теперь cosx=1 x=2pin,n €Z cosx=-4/3не сответствует ответ х=2pin
3 votes
Thanks 0
×
Report "2;3п]..."
Your name
Email
Reason
-Select Reason-
Pornographic
Defamatory
Illegal/Unlawful
Spam
Other Terms Of Service Violation
File a copyright complaint
Description
Helpful Links
О нас
Политика конфиденциальности
Правила и условия
Copyright
Контакты
Helpful Social
Get monthly updates
Submit
Copyright © 2025 SCHOLAR.TIPS - All rights reserved.
Answers & Comments
Verified answer
=3(2(cosx)^2 -1)+cosx-4=0,6cos^2(x)+cosx-7=0,
(cosx -1)(cosx -14/6)=0, cosx=1,
x=2п