[tex]\displaystyle 2,4+(x:3-5)=4\\\\\frac{12}{5}+(\frac{1}{3}x-5)=4\\ \\\frac{12}{5}+\frac{1}{3}x-5=4\\ \\-\frac{13}{5}+\frac{1}{3}x=4\\ \\-39+5x=60\\ 5x=60+39\\ 5x=99\\ \\x=\frac{99}{5}=19\frac{4}{5}=19,8[/tex]