Ответ:
решение смотри на фотографии
[tex]2)5-1\dfrac{9}{13} =4\dfrac{13}{13} -1\dfrac{9}{13} =3\dfrac{4}{13}[/tex]
[tex]\displaystyle4)9\frac{4}{5} -\frac{3}{10} =\frac{49}{5} -\frac{3}{10} =\frac{98}{10} -\frac{3}{10} =\frac{95}{10} =9\frac{5}{10}[/tex]
[tex]6)\displaystyle3\frac{3}{10} -1\frac{4}{15} =\frac{33}{10} -\frac{19}{15} =\frac{99}{30} -\frac{38}{30} =\frac{61}{30} =2\frac{1}{30}[/tex]
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Answers & Comments
Ответ:
решение смотри на фотографии
Ответ:
[tex]2)5-1\dfrac{9}{13} =4\dfrac{13}{13} -1\dfrac{9}{13} =3\dfrac{4}{13}[/tex]
[tex]\displaystyle4)9\frac{4}{5} -\frac{3}{10} =\frac{49}{5} -\frac{3}{10} =\frac{98}{10} -\frac{3}{10} =\frac{95}{10} =9\frac{5}{10}[/tex]
[tex]6)\displaystyle3\frac{3}{10} -1\frac{4}{15} =\frac{33}{10} -\frac{19}{15} =\frac{99}{30} -\frac{38}{30} =\frac{61}{30} =2\frac{1}{30}[/tex]