(sin2x+cos2x)^2 если x=-π/24 помогите пожалуйста т.т. Created by piano1234533. algebra-ru

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piano1234533 @piano1234533

July 2022 1 3 Report

(sin2x+cos2x)^2 если x=-π/24
помогите пожалуйста т.т

Answers & Comments

mukus13

Verified answer

$(sin2x+cos2x)^2=sin^22x+cos^22x+2sin2x*cos2x=1+sin4x$

$x= \frac{ \pi }{24}$

$1+sin4x=1+sin(4* \frac{ \pi }{24})=1+sin \frac{ \pi }{6} =1+ \frac{1}{2} =1.5$

Ответ: $1.5$

P.S.
$(a+b)^2=a^2+b^2+2ab$

$cos^2x+sin^2x=1$

$sin2x=2sinx*cosx$

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piano1234533 спасибо огромное!))

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