Home
О нас
Products
Services
Регистрация
Войти
Поиск
knopka1995
@knopka1995
August 2021
0
13
Report
Помогите пож-та решить очень надо срочно Решить уравнение
1) а) sinx=-1 б)cosx=√2/2 в)sinx=-1/2 г)cosx= -√3/2
2) а) tgx=1 б)ctgx= -√3 в)tgx=√3/3
3) а)sinx= -1/7 б)cosx=1/8 в)tgx= -1/2 г)cosx= - π/2
4)2√2sinx+√2sinxcosx-cosx-2=0
Please enter comments
Please enter your name.
Please enter the correct email address.
Agree to
terms of service
You must agree before submitting.
Send
More Questions From This User
See All
knopka1995
July 2022 | 0 Ответы
ml rasschitajte sostav poluchennogo rastvora v massovyh dolyah
Answer
knopka1995
July 2022 | 0 Ответы
vopros zhizni i smerti pomogite pozhalujsta lyudi dobrye ochen proshuopredelite
Answer
×
Report "2 4)2√2sinx+√2sinxcosx-cosx-2=0..."
Your name
Email
Reason
-Select Reason-
Pornographic
Defamatory
Illegal/Unlawful
Spam
Other Terms Of Service Violation
File a copyright complaint
Description
Helpful Links
О нас
Политика конфиденциальности
Правила и условия
Copyright
Контакты
Helpful Social
Get monthly updates
Submit
Copyright © 2024 SCHOLAR.TIPS - All rights reserved.