[tex]y = {x}^{2} \tg(x) \\ y' = ( {x}^{2} )' \tg(x) + {x}^{2} ( \tg(x) )' = \\ 2x \tg(x) + \frac{ {x}^{2} }{ \cos {}^{2} (x) } \\ x_{o} = \frac{\pi}{4} \\ \frac{2 \times \pi}{4} \tg( \frac{\pi}{4} ) + \frac{ (\frac{\pi}{4}) {}^{2} }{ \cos {}^{2} ( \frac{\pi }{4} ) } = \\ \frac{\pi}{2} \times 1 + \frac{ \frac{\pi {}^{2} }{16} }{ \frac{2}{4} } = \frac{\pi}{2} + \frac{\pi}{8} = \frac{4\pi + \pi {}^{2} }{8} [/tex]

Ответ: Г)