ctg(π/2+L)+tg(2π-L); 1-cos*2L+sin*2L; sin x/2= -1; cos4xcos2x-sin4xsin2x=1/2. Created by alinaatamanchuk. algebra-ru

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July 2022 1 3 Report

ctg(π/2+L)+tg(2π-L);
1-cos*2L+sin*2L;
sin x/2= -1;
cos4xcos2x-sin4xsin2x=1/2

Answers & Comments

TDNr $ctg( \pi /2+ \alpha ) +tg (2 \pi - \alpha ) = -tg \alpha - tg \alpha = -2tg \alpha$

$sin x/2= -1$
$x/2 = - \pi /2 + 2 \pi k$
$x = - \pi + 4 \pi k$

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