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Ответ:

Объяснение:

а)

Mr(N₂O₃) = Ar(N) * 2 + Ar(O) * 3 = 14 * 2 + 16 * 3 = 76

w(N) = Ar(N) * n/Mr(N₂O₃) * 100% = 14 * 2/76 * 100% = 36,84%

w(О) = Ar(О) * n/Mr(N₂O₃) * 100% = 16 * 3/76 * 100% = 63,16%

б)

Mr(MgCl₂) = Ar(Mg) + Ar(Cl) * 2 = 24 + 35 * 2 = 94

w(Mg) = Ar(Mg) * n/Mr(MgCl₂) * 100% = 24 /94 * 100% = 25,53%

w(Cl) = Ar(Cl) * n/Mr(MgCl₂) * 100% = 35 * 2/94 * 100% = 74,47%