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sultygova2000
@sultygova2000
July 2022
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решите пожалуйСТА. КТО-нибудь!!!СРОЧНО НАДО!!! 4^cosx+4^cos(П-x)=5/2
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Wdghgf
4^cosx+4^(-cosx)=5/2
4^cosx=y=>4^(-cosx)=1/y
y+1/y=5/2 (*2y)
2y²-5y+2=0
y1=1/2;y2=2
1) 4^cosx=1/2
2^(2cosx)=2^(-1)
2cosx=-1
cosx=-1/2
x=+/-2pi/3+2pin,n€Z
2) 4^cosx=2
2^(2cosx)=2^1
2cosx=1
cosx=1/2
x=+/-pi/3+2pik,k€Z
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Answers & Comments
4^cosx=y=>4^(-cosx)=1/y
y+1/y=5/2 (*2y)
2y²-5y+2=0
y1=1/2;y2=2
1) 4^cosx=1/2
2^(2cosx)=2^(-1)
2cosx=-1
cosx=-1/2
x=+/-2pi/3+2pin,n€Z
2) 4^cosx=2
2^(2cosx)=2^1
2cosx=1
cosx=1/2
x=+/-pi/3+2pik,k€Z