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valyas9797
@valyas9797
July 2022
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тригонометрия 11 класс
√2 ×sin(-13π/4)- ctg (-9π/2) =
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JulietteVi
√2 * -sin(12p/4+p/4) + ctg(8p/2 + p/2)= √2 - sin(3p +p/4)+ctg(4p+p/2)= √2+sin(p/4)+ctg(p/2)= √2+ √(2)/2 +0= 3√2 /2
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valyas9797
спасибо большое
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