2√5-4...

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August 2022 1 2 Report

cos(2x+10)=-√15+2√3/2√5-4

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ludmilagena

Verified answer

Cos(2x+10)=(-√5 *√3+2√3)/(2*(√5-2))
cos(2x+10)= - √3(2-√5)/(2*(2-√5)
cos(2x+10)= -√3/2
1) 2x+10=5π/6+2πk
2x=- 10+5π/6+2πk
x= - 5+5π/12+πk
2) 2x+10 =- 5π/6+2πk
x= -5 - 5π/12 + πk
ответ: x= -5+5π/12+πk, k∈Z
x= - 5 - 5π/12+πk, k∈Z

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