CuCl2+2KOH=>Cu(OH)2+2KCl
осад—Cu(OH)2
Mr(CuCl2)=135
n(CuCl2)=25/135=0,185моль
n(CuCl2)=n(Cu(OH)2)=0,185
Mr(Cu(OH)2)=98
m(Cu(OH)2)=98×0,185=18,13г
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Verified answer
CuCl2+2KOH=>Cu(OH)2+2KCl
осад—Cu(OH)2
Mr(CuCl2)=135
n(CuCl2)=25/135=0,185моль
n(CuCl2)=n(Cu(OH)2)=0,185
Mr(Cu(OH)2)=98
m(Cu(OH)2)=98×0,185=18,13г