1) NaCl; Al2S3
2) S - VI; C - II
3) Mr(H2SO4) = 1×2+32+16×4 = 82
4) ω(Na) =
[tex] \frac{23}{58.5} \times 100\% = 39.3\%[/tex]
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1) NaCl; Al2S3
2) S - VI; C - II
3) Mr(H2SO4) = 1×2+32+16×4 = 82
4) ω(Na) =
[tex] \frac{23}{58.5} \times 100\% = 39.3\%[/tex]