Ответ:
3) 3а(b+3)+c(b+3) при a= -0,2 ; b=1,03; c=1,6
3×(-0,2)×(1,03+3)+1,6×(1,03+3) = -0,6×(1,03+3)+1,6×(1,03+3) = -0,292+6,438 = 6,046
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Ответ:
3) 3а(b+3)+c(b+3) при a= -0,2 ; b=1,03; c=1,6
3×(-0,2)×(1,03+3)+1,6×(1,03+3) = -0,6×(1,03+3)+1,6×(1,03+3) = -0,292+6,438 = 6,046