Ответ:
[tex] {x}^{2} - 3 = 10x \\ {x}^{2} - 10x - 3 = 0[/tex]
a=1, b=-10, c=-3
[tex]x_{1,2} = \frac{ - b \pm \sqrt{ {b}^{2} - 4ac} }{2a} [/tex]
[tex]x_{1,2} = \frac{ - ( - 10) \pm \sqrt{ {( - 10)}^{2} - 4 \times 1 \times ( - 3) } }{2 \times 1} = \frac{10 \pm \sqrt{100 + 12} }{2} = \frac{10 \pm \sqrt{112} }{2} = \frac{10 \pm 2\sqrt{28} }{2} = 5 \pm \sqrt{28} [/tex]
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Ответ:
[tex] {x}^{2} - 3 = 10x \\ {x}^{2} - 10x - 3 = 0[/tex]
a=1, b=-10, c=-3
[tex]x_{1,2} = \frac{ - b \pm \sqrt{ {b}^{2} - 4ac} }{2a} [/tex]
[tex]x_{1,2} = \frac{ - ( - 10) \pm \sqrt{ {( - 10)}^{2} - 4 \times 1 \times ( - 3) } }{2 \times 1} = \frac{10 \pm \sqrt{100 + 12} }{2} = \frac{10 \pm \sqrt{112} }{2} = \frac{10 \pm 2\sqrt{28} }{2} = 5 \pm \sqrt{28} [/tex]