У простите выражение 4/y - 2/y-5 + 2y+10/25-y(в квадрате). Created by vpicajkin. algebra-ru

25-y(в квадрате)...

October 2021 2 33 Report

У простите выражение
4/y - 2/y-5 + 2y+10/25-y(в квадрате)

Almazik239

4/y - 2/y-5 + 2(y+5)/(5-y)(5+y)= 4/y - 2/y-5 + 2/5-y= 4/y + 2/5-y +2/5-y= 4/y +4/5-y= (4(5-y)+4y)/y(5-y)= (20-4y+4y)/y(5-y)= 20/y(5-y)

1 votes Thanks 0

vpicajkin Спасибо

Evgenia4836

Verified answer

$\frac{4}{y}-\frac{2}{y-5}+\frac{2y+10}{25-y}=\frac{4(5-y)(5+y) + 2y(5+y) + 2y(5+y)}{y(5-y)(5+y)} = \frac{2(5+y)(2(5-y)+y+y)}{y(5-y)(5+y)} = \frac{4*(5-y+y)}{y(5-y)}=\frac{20}{5y-y^2}$

1 votes Thanks 0

vpicajkin Спасибо

Answers & Comments

Verified answer

kakie ustrojstva sposobny prevrashat elektricheskuyu energiyu v mehanicheskuyunazvat

na poloske bumagi 1 metr postavili otmetki delyashie eyo na 4 ravnye chasti i otme

sokratite drob dayu 30 ballov za horoshij otvet

otvetit na voprosy kapitanskaya dochka 1 rasskazhite o ssore grinyova i shvabrina

рекомендуемые вопросы

Helpful Links

Helpful Social