У простите выражение 4/y - 2/y-5 + 2y+10/25-y(в квадрате). Created by vpicajkin. algebra-ru

25-y(в квадрате)...

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У простите выражение
4/y - 2/y-5 + 2y+10/25-y(в квадрате)

Almazik239

4/y - 2/y-5 + 2(y+5)/(5-y)(5+y)= 4/y - 2/y-5 + 2/5-y= 4/y + 2/5-y +2/5-y= 4/y +4/5-y= (4(5-y)+4y)/y(5-y)= (20-4y+4y)/y(5-y)= 20/y(5-y)

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vpicajkin Спасибо

Evgenia4836

Verified answer

$\frac{4}{y}-\frac{2}{y-5}+\frac{2y+10}{25-y}=\frac{4(5-y)(5+y) + 2y(5+y) + 2y(5+y)}{y(5-y)(5+y)} = \frac{2(5+y)(2(5-y)+y+y)}{y(5-y)(5+y)} = \frac{4*(5-y+y)}{y(5-y)}=\frac{20}{5y-y^2}$

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vpicajkin Спасибо

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