Доказать:
sin^6a+cos^6a=1-3/4sin^2a
(1+sin2a+cos2a)/(1+sin2a-cos2a)=ctga
(2sina-sin2a)/(2sina+sin2a)=tg^2a/2
Please enter comments
Please enter your name.
Please enter the correct email address.
You must agree before submitting.

Answers & Comments


Copyright © 2024 SCHOLAR.TIPS - All rights reserved.