2cosx-√3=0
2cosx=√3
cosx=√3/2
x=2pi*n+pi/6, n∈Z or x=2pi*m+(11/6)pi, m∈Z
[-pi/2;pi/2]
x₁=-pi/6
x₂=pi/6
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2cosx-√3=0
2cosx=√3
cosx=√3/2
x=2pi*n+pi/6, n∈Z or x=2pi*m+(11/6)pi, m∈Z
[-pi/2;pi/2]
x₁=-pi/6
x₂=pi/6