Home
О нас
Products
Services
Регистрация
Войти
Поиск
guzel0920
@guzel0920
August 2022
1
2
Report
256^sinx-20*16^sinx+64=0
Please enter comments
Please enter your name.
Please enter the correct email address.
Agree to
terms of service
You must agree before submitting.
Send
Answers & Comments
sangers1959
Verified answer
256^sinx-20*16^sinx+64=0
16^(2*sinx)-20*16^sinx+64=0
(16^sinx)²-20*16^sinx+64=0
Пусть sinx=t ⇒
t²-20t+64=0 D=144
t₁=16 ⇒ 16^sinx=16¹ sinx=1
x₁=π/2+2πn, n∈Z
t₂=4 ⇒ 16^sinx=4 4^(2*sinx)=4¹ 2*sinx=1 sinx=1/2
x₂=π/6+2πn x₃=5π/6+2πn, n∈Z.
1 votes
Thanks 3
рекомендуемые вопросы
rarrrrrrrr
August 2022 | 0 Ответы
o chem dolzhny pozabotitsya v pervuyu ochered vzroslye pri organizacionnom vyvoze n
danilarsentev
August 2022 | 0 Ответы
est dva stanka na kotoryh vypuskayut odinakovye zapchasti odin proizvodit a zapcha
myachina8
August 2022 | 0 Ответы
najti po grafiku otnoshenie v3v1 v otvetah napisano 9 no nuzhno reshenie
ydpmn7cn6w
August 2022 | 0 Ответы
Choose the correct preposition: 1.I am fond (out,of,from) literature. 2.where ar...
millermilena658
August 2022 | 0 Ответы
opredelite kak sozdavalas i kto sozdaval arabskoe gosudarstvo v kracii
MrZooM222
August 2022 | 0 Ответы
ch ajtmanov v rasskaze krasnoe yabloko ispolzuet metod rasskaz v rasskaze opi
timobila47
August 2022 | 0 Ответы
kakovo bylo naznachenie kazhdoj iz chastej vizantijskogo hrama pomogite pozhalujsta
ivanyyaremkiv
August 2022 | 0 Ответы
moment. 6....
pozhalujsta8b98a56c0152a07b8f4cbcd89aa2f01e 97513
sarvinozwakirjanova
August 2022 | 0 Ответы
pomogite pozhalusto pzha519d7eb8246a08ab0df06cc59e9dedb 6631
×
Report "256^sinx-20*16^sinx+64=0..."
Your name
Email
Reason
-Select Reason-
Pornographic
Defamatory
Illegal/Unlawful
Spam
Other Terms Of Service Violation
File a copyright complaint
Description
Helpful Links
О нас
Политика конфиденциальности
Правила и условия
Copyright
Контакты
Helpful Social
Get monthly updates
Submit
Copyright © 2024 SCHOLAR.TIPS - All rights reserved.
Answers & Comments
Verified answer
256^sinx-20*16^sinx+64=016^(2*sinx)-20*16^sinx+64=0
(16^sinx)²-20*16^sinx+64=0
Пусть sinx=t ⇒
t²-20t+64=0 D=144
t₁=16 ⇒ 16^sinx=16¹ sinx=1 x₁=π/2+2πn, n∈Z
t₂=4 ⇒ 16^sinx=4 4^(2*sinx)=4¹ 2*sinx=1 sinx=1/2
x₂=π/6+2πn x₃=5π/6+2πn, n∈Z.