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olegpoletaev
@olegpoletaev
July 2022
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Помогите пожалуйста вычислить, решение писменно:
1)arccos √2/2
2)arccos (- 1/2)
3)1/2arccos √3/2+ 1/3 arccos (-√2/2)
4)0,7 arcsin0 + arcsin ( -1/2)
5)1/2 arcsin (-√3/2) + arccos (-√3/2)
6)arctg (-arccos (-√2/2)/arcsin 1/2
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kamron971
Вам следует запомнить их
1) arccos√2/2 =π/4
2)arccos(-1/2)=2π/3
3)1/2arccos √3/2+1/3arccos(-√2/2)=1/2× π/6+1/3× 3π/4=π/12+π/4=3π+π / 12=4π/12=π/3
4)0,7 arcsin 0 +arcsin(-1/2)= 0,7 ×0 - π/3=-π/3
5)1/2 arcsin (-√3/2)+ arccos(-√3/2)=1/2 × (-π/3)+2π/6=-π/6+2π/6=π/6
6)arctg(-arccos(-√2/2)/arcsin1/2=acrtg(-(π-π/4))/π/6=arctg(-3π/4)/π/6=
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Answers & Comments
1) arccos√2/2 =π/4
2)arccos(-1/2)=2π/3
3)1/2arccos √3/2+1/3arccos(-√2/2)=1/2× π/6+1/3× 3π/4=π/12+π/4=3π+π / 12=4π/12=π/3
4)0,7 arcsin 0 +arcsin(-1/2)= 0,7 ×0 - π/3=-π/3
5)1/2 arcsin (-√3/2)+ arccos(-√3/2)=1/2 × (-π/3)+2π/6=-π/6+2π/6=π/6
6)arctg(-arccos(-√2/2)/arcsin1/2=acrtg(-(π-π/4))/π/6=arctg(-3π/4)/π/6=