Решить уравнения:
1) 2sin^2x + 3cosx = 0
2) (cos3x-sinx) / sinx = 0
3) 1 - cosx = sin x/2
More Questions From This User See All
Решить уравнения:
1) 2sin^2x + 3cosx = 0
2) (cos3x-sinx) / sinx = 0
3) 1 - cosx = sin x/2
Copyright © 2024 SCHOLAR.TIPS - All rights reserved.
Answers & Comments
2Cos^2x-3cosx-2=0
D=9+4*2*2=25=5^2
X=2
X=-0.5
2sin
+cosx+cosx
-sinx
=0
sin
+cosx-sin
+1=0
cosx+1=0
cosx=-1
(cosx+cosx
-sinx
-sinx)/sinx=0
(cosx(1+cosx))/sinx-(sinx(sinx+1)/sinx)=0
(cosx(1+cosx))/sinx=-1-sinx
cosx+cosx
=-sinx-sinx
cosx
+sinx
=-cosx-sinx
cosx+sinx=-1
2-2cosx=sinx
2-cos
-sin
=sinx
2=sinx+cosx
+sinx
2=sinx+1
sinx=1